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Chemical Reactions Part I - Ahmad Kilani

 In this class, we learned about 3 types of chemical reactions. Synthesis, Decompostion, and Single Replacement. 


The first one is Synthesis. 
A synthesis reaction is when two or more simple compounds combine to form a more complicated one. These reactions come in the general form of:

A + B ---> AB
One example of a synthesis reaction is the combination of iron and sulfur to form iron (II) sulfide:
8 Fe + S8 ---> 8 FeS


The second reaction is Decomposition.
A decomposition reaction is the opposite of a synthesis reaction - a complex molecule breaks down to make simpler ones. These reactions come in the general form:
 
AB ---> A + B
One example of a decomposition reaction is the electrolysis of water to make oxygen and hydrogen gas:
2 H2O ---> 2 H2 + O2


The last one (for now) is Single Replacement.
This is when one element trades places with another element in a compound. These reactions come in the general form of:

A + BC ---> AC + B
One example of a Single Resplacement reaction is when magnesium replaces hydrogen in water to make magnesium hydroxide and hydrogen gas:
Mg + 2 H2O ---> Mg(OH)2 + H2




We also learned  how to tell if a single-replacement reaction would actually take place or not depending on the reactivity of the metal/nonmetal that's being reacted with:

If the metal/nonmetal is less reactive then no reaction takes place.  for example;

Mg + Cu(NO3)2 ---> Mg(NO3)2 + Cu  

-  This equation DOES take place since Magnesium is more reactive than Copper

2KI + 1Cl2 --->  2KCl + 1I2

-  Same thing can be done with non-metals.  Single replacement of non-metals.





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January 25th Blog Post.

So this class we relearned how to balance equations. It's a very basic thing to do, both the reactant side and the product side must be equal.

Some Steps:

1)  I create a list with values of each molecule in the equation, you can do this in your head like me or as work writing on a separate piece of paper.

2)Try to balance the lowest number of molecules on each side. You balance equations by finding a number and multiplying trying to make the equation equal.

3) Look out for  diatomic elements because they have a subscript of 2.  NEVER USE DECIMALS

An example. 

Al + O2                               ------->                                              Al2O3
On the left you have                                                   On the right you have

1Al and 2O                                                              2Al and 3O

Now you have to find numbers that will balance this equation. 

If I add 4 to Aluminum  and 3 to Oxygen

I would have 4 Al and 6O ( But we write 3O2).  Now I have to find a number that works with Al2 and O3

Al4 + 3O2 --------> 2Al2O3 (The first two multiplies everything in the compound.) 

A youtube video which should help.


Random Chemistry Joke of the day.

If H2O is the formula for water was is the formula for ice???







H20 Cubed.


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January 11-- marcus lu

MOLAR VOLUME OF A GAS AT STP!

STP stands for Standard Temperatures and Pressure.  At STP, 1 mole of gas is equal to 22.4 Litres, and is also

0 degrees Celsius, or 273.14K.

CONVERTING

We can convert with these 2 formulas ----  22.4L of gas            and                  1 Mole of Gas
                                                                ----------------                              ---------------------
                                                                  1 Mole of Gas                                    22.4L of gas


1)  Calculate the volume occupied by 5.2 grams of ammonia at STP.  (NH3)

First, convert the 5.2g of ammonia to MOLES.


5.2g ammonia X 1 mole / 17g = 0.3 Moles

Secondly,  convert the moles to litres !



0.3 moles X 22.4L / 1 Mole =  7 Litres






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Jan 9th-Nick kim

 Today we have learned how to how to make solution into more concentrated form
-main idea is to know that no matter how solution has become concentraded, it still has same amount of mole
 Therefore, when solution become more concentrated only its volume and molarity


 Equation:

 
Example

I have 20.0ml of 0.200M NaOH solution but i need 100.0ml of NaOH .Calculate the new concentration.

Equation:
L1M1=L2M2

20.0ml x 0.200M = 100.0ml x M2
4mol=100.0mlM2
4mol/100ml=M2

Therefore M2(new concentration) is 0.04ml

here are video that will help
http://www.youtube.com/watch?v=0dRwHZCDBp4

practice questions
http://www.youtube.com/watch?v=KM2uzc8msas&feature=related
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January 6 - Molarily

Basically, the main concept of this lesson is that  "Molarily (M) = Moles/Litres";

The lesson is pretty straight forward so I'll just put some examples here.

1) let's say you have  2.5g of NaCl and a 10L solution, what is the molarity?

2.5g of NaCl = 0.0427 moles ; 0.0427moles/10L = 0.0043 moles/L

2) Another example would be, if u had a solution of KCl with a molarity of 6.1 and 4.5 Liters how many grams r there?

6.1 = mol/4.5                        27.45 mol x 74.6g/mol = 2047.77g ; 2.0E3 grams of KCl
mol = 27.45






 
Here's an explanation on how to deal with Molarily:
 
 




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